Squares, Cubes, and Beyond
Radical expressionsAn expression that contains a radical. are expressions that contain radicals. Radical expressions come in many forms, from simple and familiar, such as `sqrt16` , to quite complicated, as in `root(3)(250x^4y)`. In addition to square roots, there are radicals called cube roots, fourth roots, fifth roots, and so on. Using factoring, you can simplify these radical expressions, too.
Radical expressions will sometimes include variables as well as numbers. Consider the expression `sqrt(9x^6y^4)`. To simplify a radical expression such as this, you can use factoring, but you’ll have to apply the rules of exponents, too. Let’s try it.
Example |
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Problem |
Simplify. `sqrt (9x^6y^4)` |
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`sqrt(3*3*x^6y^4)` |
Factor the coefficient `9` into `3*3`. |
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`sqrt(3*3*x^2*x^2*x^2*y^2*y^2` |
Factor variables into squares. |
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`sqrt(3^2)*sqrt(x^2)*sqrt(x^2)*sqrt(x^2)*sqrt(y^2)*sqrt(y^2)` |
Write `3 * 3` as `3^2` and separate into individual radicals. |
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`3*x*x*x*y*y` |
Simplify, using the rule that`sqrt(x^2)=x`. |
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`3x^3y^2` |
Rewrite the expression with constants in front and using exponents for the variables. |
Answer |
`sqrt (9x^6y^4)=3x^3y^2` |
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The goal is to find factors under the radical that are perfect squares so that you can take their square root. Let’s repeat the example above and focus on finding identical pairs of factors.
Example |
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Problem |
Simplify. `sqrt(9x^6y^4)` |
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`sqrt(3*3*x^3*x^3*y^2*y^2` |
Factor to find identical pairs. |
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`sqrt((3^2)*(x^3)^2*(y^2)^2)` |
Rewrite the pairs as perfect squares. |
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`sqrt(3^2)*sqrt((x^3)^2)*sqrt((y^2)^2)` |
Separate into individual radicals. |
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`3x^3y^2` |
Simplify, using the rule that `sqrt(x^2)=x`. |
Answer |
`sqrt(9x^6y^4)=3x^3y^2` |
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Variable factors with even exponents can be written as squares. In the example above, `x^6=x^3*x^3=(x^3)^2` and `y^4=y^2*y^2=(y^2)^2`. Let’s try to simplify another radical expression.
Example |
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Problem |
Simplify. `sqrt(49x^10y^8)` |
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`sqrt(7*7*x^5*x^5*y^4*y^4)` |
Look for squared numbers and variables. Factor `49` into `7*7`, `x^10` into `x^5 * x^5`, and `y^8` into `y^4 * y^4`. |
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`sqrt(7^2*(x^5)^2*(y^4)^2)` |
Rewrite the pairs as squares. |
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`sqrt(7^2)*sqrt((x^5)^2)*sqrt((y^4)^2)` |
Separate the squared factors into individual radicals. |
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`7*x^5*y^4` |
Take the square root of each radical using the rule that `sqrt(x^2)=x`. |
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`7x^5y^4` |
Multiply. |
Answer |
`sqrt(49x^10y^8)=7x^5y^4` |
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You find that the square root of `49x^10y^8` is `7x^5y^4`. In order to check this calculation, you could square `7x^5y^4`, hoping to arrive at `49x^10y^8`. And, in fact, you would get this expression if you evaluated `(7x^5y^4)^2`.
Take a moment to think about two radical expressions: `sqrt900` and `sqrt(a^3b^5c^7)`. You would use the same techniques to simplify either one of these: find squares within the radical, rewrite the expression as the product of separate radicals, simplify and multiply.
There is an added issue when you are taking the root of a radical expression that contains variables. Recall that the root of an integer, such as `sqrt900`, is defined to be nonnegative. This means that although both `30^2` and `(-30)^2` are equal to `900`, `sqrt900` is defined only as `30`. This is the idea behind `30` being the principal rootThe positive square root of a number, as in `sqrt16=4`. By definition, the radical symbol always means to find the principal root. Note that zero has only one square root, itself (since `0 * 0 = 0`). of `900`.
But it is not as straightforward with radical expressions that contain variables. Consider the expression `sqrt(x^2)`. This looks like it should be equal to `x`, right? Let’s test some values for `x` and see what happens.
In the chart below, look along each row and determine whether the value of `x` is the same as the value of `sqrt(x^2)`. Where are they equal? Where are they not equal?
After doing that for each row, look again and determine whether the value of `sqrt(x^2)` is the same as the value of `|x|`.
`x` |
`x^2` |
`sqrt(x^2)` |
`|x|` |
`-5` |
`25` |
`5` |
`5` |
`-2` |
`4` |
`2` |
`2` |
`0` |
`0` |
`0` |
`0` |
`6` |
`36` |
`6` |
`6` |
`10` |
`100` |
`10` |
`10` |
Notice in cases where `x` is a negative number, `sqrt(x^2)!=x`! (This happens because the process of squaring the number loses the negative sign, since a negative times a negative is a positive.) However, in all cases `sqrt(x^2)=|x|`. You need to consider this fact when simplifying radicals that contain variables, because by definition `sqrt(x^2)` is always nonnegative.
Taking the Square Root of a Radical Expression
When finding the square root of an expression that contains variables raised to a power, consider that `sqrt(x^2)=|x|`.
Examples: `sqrt(9x^2)=3|x|`, and `sqrt(16x^2y^2)=4|xy|`
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Look at how this idea is applied in this next example.
Example |
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Problem |
Simplify. `sqrt(a^3b^5c^2)` |
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`sqrt(a^2*a*b^4*b*c^2)` |
Factor to find variables with even exponents. |
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`sqrt(a^2*a*(b^2)^2*b*c^2)` |
Rewrite `b^4` as `(b^2)^2`. |
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`sqrt(a^2)*sqrt((b^2)^2)*sqrt(c^2)*sqrt(a*b)` |
Separate the squared factors into individual radicals. |
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`|a|*b^2*|c|*sqrt(a*b)` |
Take the square root of each radical. Remember that `sqrt(a^2)=|a|`. |
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`|ab^2c|sqrt(ab)` |
Simplify and multiply. The entire quantity `ab^2c` can be enclosed in the absolute value sign because `b^2` will be positive, so its inclusion has no effect. |
Answer |
`sqrt(a^3b^5c^2)=|ab^2c|sqrt(ab)` |
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Simplify. `sqrt(72y^2z^3)`
A) `36yzsqrtz`
B) `6sqrt(2y^2z^3)`
C) `6yzsqrt(2z)`
D) `6|yz|sqrt(2z)`
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While square roots are probably the most common radical, you can also find the third root, the fifth root, the `10`th root, or really any other `n`th root of a number. Just as the square root is a number that, when squared, gives the radicand, the cube root The number which, when multiplied together three times yields the original number. For example, the cube root of `64` is `4` because `4 * 4 * 4 = 64`. is a number that, when cubed, gives the radicand. Cubing a number is the same as taking it to the third power: `2^3` is `2` cubed, so the cube root of `2^3` is `2`.
The cube root of a number is written with a small number `3`, called the index The small positive integer just outside and above the radical symbol that denotes the root. For example, `root(3)(\ )` denotes the cube root. , just outside and above the radical symbol. It looks like `root(3)(\ )`. This little `3` distinguishes cube roots from square roots, which are written without a small number outside and above the radical symbol.
Be careful to distinguish between `root(3)(x)` , the cube root of `x`, and `3sqrtx`, three times the square root of `x`. They may look similar at first, but they lead you to much different expressions!
Example |
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Problem |
Simplify. `root(3)(8)` |
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`2 * 2 * 2` |
Ask yourself, “What number can I multiply by itself, and then by itself again, to get `8`?” |
Answer |
`root(3)(8)=2` |
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Another approach to simplifying a cube root is to use factoring. Let’s explore factoring with the expression `root(3)(125)`. You can read this as “the third root of `125`” or “the cube root of `125`.” To simplify this expression, look for a number that, when multiplied by itself two times (for a total of three identical factors), equals `125`. Let’s factor `125` and find that number.
Example |
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Problem |
Simplify. `root(3)(125)` |
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`root(3)(5*25)` |
`125` ends in `5`, so you know that `5` is a factor. Expand `125` into `5*25`. |
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`root(3)(5*5*5)` |
Factor `25` into `5` and `5`. |
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`root(3)(5^3)` |
The factors are `5*5*5`, or `5^3`. |
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Answer |
`root(3)(125)=5` |
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The prime factors of `125` are `5*5*5`, which can be rewritten as `5^3`. The cube root of a cubed number is the number itself, so `root(3)(5^3)=5`. You have found the cube root, the three identical factors that when multiplied together give `125`. `125` is known as a perfect cubeA number whose cube root is an integer. because its cube root is an integer.
Here’s an example of how to simplify a radical that is not a perfect cube.
Example |
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Problem |
Simplify. `root(3)(32m^5)` |
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`root(3)(2*2*2*2*2*m^5)` |
Factor `32` into prime factors. |
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`root(3)(2^3*2*2*m^5)` |
Since you are looking for the cube root, you need to find factors that appear `3` times under the radical. Rewrite `2*2*2` as `2^3`. |
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`root(3)(2^3*2*2*m^3*m^2)` |
Rewrite `m^5` as `m^3*m^2`. |
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`root(3)(2^3)*root(3)(2*2)*root(3)(m^3)*root(3)(m^2)` |
Rewrite the expression as a product of multiple radicals. |
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`2*root(3)(4)*m*root(3)(m^2)` |
Simplify and multiply. |
Answer |
`root(3)(32m^5)=2m root(3)(4m^2)` |
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Simplify. `root(3)(64h^6)`
A) `8h^3`
B) `8sqrt(h^6)`
C) `4+h^2`
D) `4h^2`
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There is one interesting fact about cube roots that is not true of square roots. Negative numbers can’t have real number square roots, but negative numbers can have real number cube roots! What is the cube root of `-8`? `root(3)(-8)=-2` because `-2*-2*-2=-8`. Remember, when you are multiplying an odd number of negative numbers, the result is negative! In the example below, notice how `root(3)((-1)^3)=-1` is used to simplify the radical.
Example |
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Problem |
Simplify. `root(3)(-27x^4y^3)` |
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`root(3)(-1*27*x^4*y^3)` `root(3)((-1)^3*(3)^3*x^3*x*y^3)`
`root(3)(-1^3)*root(3)((3)^3)*root(3)(x^3)*root(3)(x)*root(3)(y^3)` |
Factor the expression into cubes.
Separate the cubed factors into individual radicals. |
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`-1*3*x*y*root(3)(x)` |
Simplify the cube roots. |
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Answer |
`root(3)(-27x^4y^3)=-3xyroot(3)(x)` |
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You could check your answer by performing the inverse operation. If you are right, when you cube `-3xyroot(3)(x)` you should get `-27x^4y^3`.
`(-3xyroot(3)(x))(-3xyroot(3)(x))(-3xyroot(3)(x))`
`-3*-3*-3*x*x*x*y*y*y*root(3)(x)*root(3)(x)*root(3)(x)`
`-27*x^3*y^3*root(3)(x^3)`
`-27x^3y^3*x`
`-27x^4y^3`
So, you can find the odd root of a negative number, but you cannot find the even root of a negative number. This means you can simplify the radicals `root(3)(-81), root(5)(-64)`, and `root(7)(-2187)`, but you cannot simplify the radicals `sqrt(-100), root(4)(-16)`, or `root(6)(-2,500)`.
Let’s look at another example.
Example |
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Problem |
Simplify. `root(3)(-24a^5)` |
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`root(3)(-1*8*3*a^5)` |
Factor `-24` to find perfect cubes. Here, `-1` and `8` are the perfect cubes. |
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`root(3)((-1)^3*2^3*3*a^3*a^2)` |
Factor variables. You are looking for cube exponents, so you factor `a^5` into `a^3` and `a^2`.
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`root(3)(-1^3)*root(3)(2^3)*root(3)(a^3)*root(3)(3*a^2)` |
Separate the factors into individual radicals. |
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`-1*2*a*root(3)(3*a^2)` |
Simplify, using the property `root(3)(x^3)=x`. |
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`-2a root(3)(3a^2)` |
This is the simplest form of this expression; all cubes have been pulled out of the radical expression. |
Answer |
`root(3)(-24a^5)=-2a root(3)(3a^2)` |
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The steps to consider when simplifying a radical are outlined below.
Simplifying a radical
When working with exponents and radicals:
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Example |
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Problem |
Simplify. `sqrt(100x^2y^4\)` |
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`sqrt(10*10*x^2*y^4)` |
Separate factors; look for squared numbers and variables. Factor `100` into `10*10`. |
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`sqrt(10*10*x^2*(y^2)^2)` |
Factor `y^4` into `(y^2)^2`. |
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`sqrt(10^2)*sqrt(x^2)*sqrt((y^2)^2)` |
Separate the squared factors into individual radicals. |
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`10*|x|*y^2` |
Take the square root of each radical. Since you do not know whether `x` is positive or negative, use ` |x|` to account for both possibilities, thereby guaranteeing that your answer will be positive. |
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`10|x|y^2` |
Simplify and multiply. |
Answer |
`sqrt(100x^2y^4)=10|x|y^2` |
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You can check your answer by squaring it to be sure it equals `100x^2y^4`.
A radical expression is a mathematical way of representing the `n`th root of a number. Square roots and cube roots are the most common radicals, but a root can be any number. To simplify radical expressions, look for exponential factors within the radical, and then use the property `root(n)(x^n)=x` if `n` is odd, and `root(n)(x^n)=|x|` if `n` is even to pull out quantities. All rules of integer operations and exponents apply when simplifying radical expressions.