Introduction to Single Variable Polynomials

 

Learning Objective(s)

·         Identify the terms, the coefficients and the exponents of a polynomial.

·         Evaluate a polynomial for given values of the variable.

·         Simplify polynomials by collecting like terms.

 

 

Introduction

 

Algebraic expressions are created by combining numbers and variables using arithmetic operations: addition, subtraction, multiplication, division, and exponentiation. Using all but division, you can create an expression called a polynomial by adding or subtracting terms. Polynomials are very useful in applications from science and engineering to business. Monomials (and polynomials in general) may have more than one variable, but in this unit, you will only work with single variable polynomials.

 

 

Monomials

 

The basic building block of a polynomial is a monomial. A monomial is one term and can be a number, a variable, or the product of a number and variables with an exponent. The number part of the term is called the coefficient.

 

 

 

The coefficient can be any real number, including 0. The exponent of the variable must be a whole number—0, 1, 2, 3, and so on. A monomial cannot have a variable in the denominator or a negative exponent.

 

The value of the exponent is the degree of the monomial. Remember that a variable that appears to have no exponent really has an exponent of 1. And a monomial with no variable has a degree of 0. (Since x0 has the value of 1 if x ≠ 0, a number such as 3 could also be written 3x0, if x ≠ 0. as 3x0 = 3 • 1 = 3.)

 

 

Example

Problem

Identify the coefficient, variable, and exponent of the monomial .

Answer

The variable is k.

The exponent of k is 8.

The coefficient of k8 is .

 

 

Example

Problem

Identify the coefficient, variable, and exponent of x.

Answer

The variable is x.

 

 

The exponent of x is 1.

x = x1, so the exponent is 1.

 

The coefficient of x is 1.

x = 1x1 so the coefficient is also 1.

 

 

Identify the coefficient, variable, and exponent of 3y.

 

A) The variable is y, the exponent is 3, and the coefficient is 1.

B) The variable is y, the exponent is 0, and the coefficient is 3.

C) The variable is y, the exponent is 1, and the coefficient is 3.

D) The variable is y, the exponent is 3, and the monomial has no coefficient.

 

Show/Hide Answer

A) The variable is y, the exponent is 3, and the coefficient is 1.

Incorrect. The exponent is the power of the variable and the coefficient is the number before the variable. The coefficient in this case is 3, and the exponent is 1 because 3y = 3y1.

 

B) The variable is y, the exponent is 0, and the coefficient is 3.

Incorrect. The coefficient is 3, but the exponent is 1 because 3y = 3y1. An exponent of 0 would be 3y0, and since y0 = 1 when y ≠ 0, this would be equal to 3 (when y ≠ 0).

 

C) The variable is y, the exponent is 1, and the coefficient is 3.

Correct. The coefficient is 3, the variable is y, and the exponent is 1 because 3y = 3y1.

 

D) The variable is y, the exponent is 3, and the monomial has no coefficient.

Incorrect. The exponent is the power of the variable and the coefficient is the number before the variable. The coefficient in this case is 3, and the exponent is 1 because 3y = 3y1.

 

 

 

Naming and Writing Polynomials

 

A polynomial is a monomial or the sum or difference of two or more polynomials. Each monomial is called a term of the polynomial.

 

Some polynomials have specific names indicated by their prefix.

 

monomial – is a polynomial with exactly one term (“mono” – means one)

binomial – is a polynomial with exactly two terms (“bi” – means two)

trinomial – is a polynomial with exactly three terms (“tri” – means three)

 

The word “polynomial” has the prefix, “poly,” which means many. However, the word polynomial can be used for all numbers of terms, including only one term.

 

Because the exponent of the variable must be a whole number, monomials and polynomials cannot have a variable in the denominator.

 

Polynomials can be classified by the degree of the polynomial. The degree of a polynomial is the degree of its highest degree term. So the degree of 2x3 + 3x2 + 8x + 5 is 3.

 

A polynomial is said to be written in standard form when the terms are arranged from the highest degree to the lowest degree. When it is written in standard form it is easy to determine the degree of the polynomial.

 

The table below illustrates some examples of monomials, binomials, trinomials, and other polynomials. They are all written in standard form.

 

Monomials

Binomials

Trinomials

Other Polynomials

15

3y + 13

x3 x2 + 1

5x4 + 3x3 – 6x2 + 2x

x

4p – 7

3x2 + 2x – 9

x5 – 2x4 + x3x2 + 4x

-4y3

3x2 + x

3y3 + y2 – 2

3t3 – 3t2 – 3t – 3

16n4

14y3 + 3y

a7 + 2a5 – 3a3

q7 + 2q5 – 3q3 + q

 

When the coefficient of a polynomial term is 0, you usually do not write the term at all (because 0 times anything is 0, and adding 0 doesn’t change the value). The last binomial above could be written as a trinomial, 14y3 + 0y2 + 3y.

 

A term without a variable is called a constant term, and the degree of that term is 0. For example 13 is the constant term in 3y + 13. You would usually say that 14y3 + 3y has no constant term or that the constant term is 0.

 

 

Which of the following expressions are polynomials?

 

2x4 − 3x3

 

14

 

 

A) Only 2x4 − 3x3 and  are polynomials.

B) Only 2x4 − 3x3 and 14 are polynomials.

C) Only 2x4 − 3x3 is a polynomial.

D) None of the expressions is a polynomial.

 

Show/Hide Answer

A) Only 2x4 − 3x3 and  are polynomials.

Incorrect.  is not a polynomial because it has a variable in the denominator. The correct answer is 2x4 – 3x3 and 14.

 

B) Only 2x4 − 3x3 and 14 are polynomials.

Correct.  is not a polynomial because it has a variable in the denominator.

 

C) Only 2x4 − 3x3 is a polynomial.

Incorrect. 14 is also a monomial, a type of polynomial. The correct answer is 2x4 – 3x3 and 14.

 

D) None of the expressions is a polynomial.

Incorrect. x4 – 3y3 and 14 are polynomials.  is not a polynomial because it has a variable in the denominator.

 

 

 

Evaluating Polynomials

 

You can evaluate polynomials just as you have been evaluating expressions all along. To evaluate an expression for a value of the variable, you substitute the value for the variable every time it appears. Then use the order of operations to find the resulting value for the expression.

 

 

Example

Problem

Evaluate 3x2 – 2x + 1 for x = -1.

 

3(-1)2 – 2(-1) + 1

Substitute -1 for each x in the polynomial.

 

3(1) – 2(-1) + 1

Following the order of operations, evaluate exponents first.

 

3 + (-2)(-1) + 1

Multiply 3 times 1, and then multiply -2 times -1.

 

3 + 2 + 1

Change the subtraction to addition of the opposite.

Answer

3x2 – 2x + 1 = 6, for x = 1

Find the sum.

 

 

Example

Problem

Evaluate  for p = 3.

 

(3)4 + 2(3)3 – 3

Substitute 3 for each p in the polynomial.

 

(81) + 2(27) – 3

Following the order of operations, evaluate exponents first and then multiply.

 

-54 + 54 – 3

Add and then subtract to get -3.

Answer

p4 + 2p3p = 3, for p = 3

 

 

Evaluate 3x3 − 2x2 for x = -2.

 

A) -24 – 2x2

B) -32

C) -16

D) 16

 

 

Show/Hide Answer

A) -24 – 2x2

Incorrect. x = -2 for all appearances of x in the expression. You must substitute -2 into both instances: 3(-2)3 – 2(-2)2. The correct answer is -32.

 

B) -32

Correct. Since x = -2, 3x3 − 2x2 = 3(-2)3 – 2(-2)2 = 3(-8) – 2(4) = -24 – 8 = -32.

 

C) -16

Incorrect. You may have forgotten that (-2)2 is positive, or made another mistake in your calculations. Since x = -2, 3x3 − 2x2 = 3(-2)3 – 2(-2)2 = 3(-8) – 2(4) = -24 – 8 = -32.

 

D) 16

Incorrect. You may have forgotten that (-2)3 is negative (the product of two negative values is positive, so multiplying by a third negative gives a negative product). Since x = -2, 3x3 − 2x2 = 3(-2)3 – 2(-2)2 = 3(-8) – 2(4) = -24 – 8 = -32.

 

 

 

Simplifying Polynomials

 

A polynomial may need to be simplified. One way to simplify a polynomial is to combine the like terms if there are any. Two or more terms in a polynomial are like terms if they have the same variable (or variables) with the same exponent. For example, 3x2 and -5x2 are like terms: They both have x as the variable, and the exponent is 2 for each. However, 3x2 and 3x are not like terms, because their exponents are different.

 

Here are some examples of terms that are like and some that are unlike.

 

 

Monomials

Terms

Explanation

3x

 

14x

like

same variables with same exponents

16z2

 

-5z2

like

same variables with same exponents

3x

 

5y

 

unlike

different variables (although the same exponents)

-3z

 

-3z2

unlike

same variables but with different exponents

 

 

Example

Problem

Which of these terms are like terms?

7x3   7x   7y   8x3   9y   3x2   8y2

 

x:   7x3  7x  -8x3  -3x2

y:   7y  9y  8y2

Like terms must have the same variables, so first identify which terms use the same variables.

 

The x terms 7x3 and 8x3 have the same exponent.

 

The y terms 7y and 9y have the same exponent.

Like terms must also have the same exponents. Identify which terms with the same variables also use the same exponents.

Answer

7x3 and 8x3 are like terms.

7y and 9y are like terms.

 

 

 

Which of these are like terms?

 

3a   3a2   8b   3b3   8a   14b2   9a

 

A) Only 3a, 8a, and 9a are like terms.

B) Only 8a and 9a are like terms.

C) 8b, 3b3, and 14b2 are like terms, and 3a, 3a2, 8a, and 9a are like terms.

D) 3a2 and 14b2  are like terms, and 3a, 8b, 8a, and 9a are like terms.

 

Show/Hide Answer

A) Only 3a, 8a, and 9a are like terms.

Correct. These terms have the same variable, a, with an exponent of 1.

 

B) Only 8a and 9a are like terms.

Incorrect. -3a also is a like term with 8a and 9a, because it has the same variable with the same exponent.

 

C) 8b, 3b3, and 14b2 are like terms, and 3a, 3a2, 8a, and 9a are like terms.

Incorrect. Each group has the same variable, but their exponents are different. The only terms with the same variable and exponent are 3a, 8a, and 9a.

 

D) 3a2 and 14b2  are like terms, and 3a, 8b, 8a, and 9a are like terms.

Incorrect. Each group has the same exponent, but their variables are different. The only terms with the same variable and exponent are 3a, 8a, and 9a.

 

 

 

You can use the distributive property to simplify the sum of like terms. Recall that the distributive property of addition states that the product of a number and a sum (or difference) is equal to the sum (or difference) of the products.

 

                        2(3 + 6) = 2(3) + 2(6)

 

Both expressions equal 18. So you can write the expression in whichever form is the most useful.

 

Let’s see how we can use this property to combine like terms.

 

 

Example

Problem

Simplify 3x2 – 5x2.

 

3(x2) – 5(x2)

3xand 5x2 are like terms.

 

(3 – 5)(x2)

We can rewrite the expression as the product of the difference.

 

 

 

(-2)(x2)

Calculate 3 – 5.

Answer

3x2 – 5x2 = −2x2

Write the difference of 3 – 5 as the new coefficient.

 

 

You may have noticed that combining like terms involves combining the coefficients to find the new coefficient of the like term. You can use this as a shortcut.

 

 

Example

Problem

Simplify 6a4 + 4a4.

 

6a4 + 4a4

Notice that both terms have a number multiplied by a4. This makes them like terms.

 

(6 + 4)(a4)

Combine the coefficients, 6 and 4.

 

(10)(a4)

Calculate the sum.

Answer

6a4 + 4a4 = 10a4

Write the sum as the new coefficient.

 

 

When you have a polynomial with more terms, you have to be careful that you combine only like terms. If two terms are not like terms, you can’t combine them.

 

 

Example

Problem

Simplify 3x2 + 3x + x + 1 + 5x.

 

3x, x, and 5x are like terms

First identify which terms are like terms: only 3x, x, and 5x are like terms.

 

3x2 + 3x + x + 1 + 5x =


3x2 + (3x + x + 5x) + 1

Use the commutative and associative properties to group the like terms together.

 

3x2 + (3 + 1 + 5)x + 1

Add the coefficients of the like terms. Remember that the coefficient of x is 1 (x = 1x ).

 

3x2 + (9)x + 1

 

Answer

3x2 + 3x + x + 1 + 5x =

3x2 + 9x + 1

Write the sum as the new coefficient.

 

 

Simplify by combining like terms.

 

-3a + 3a2 + 8a + 9a – 3

 

A) 3a2 + 17a – 3

B) 3a2 + 14a – 3

C) 17a – 3

D) 17a – 3a – 3

 

Show/Hide Answer

A) 3a2 + 17a – 3

Incorrect. There are three terms with a (remember that a1 is written as a): -3a, 8a, and 9a. Combining them gives -3a + 8a + 9a = (-3 + 8 + 9)a = 14a, so the simplified polynomial is 3a2 + 14a – 3.

 

B) 3a2 + 14a – 3

Correct. There are three terms with a (remember that a1 is written as a): -3a, 8a, and 9a. Combining them gives -3a + 8a + 9a = (-3 + 8 + 9)a = 14a, so the simplified polynomial is 3a2 + 14a – 3.

 

C) 17a – 3

Incorrect. You may have incorrectly combined the first two terms, -3a + 3a2. These are not like terms, so you can’t combine them. There are three terms with a (remember that a1 is written as a): -3a, 8a, and 9a. Combining them gives -3a + 8a + 9a = (-3 + 8 + 9)a = 14a, so the simplified polynomial is 3a2 + 14a – 3.

 

D) 17a – 3a – 3

Incorrect. There are three terms with a (remember that a1 is written as a): -3a, 8a, and 9a. Combining them gives -3a + 8a + 9a = (-3 + 8 + 9)a = 14a, so the simplified polynomial is 3a2 + 14a – 3.

 

 

 

Summary

 

Polynomials are algebraic expressions that contain any number of terms combined by using addition or subtraction. A term is a number, a variable, or a product of a number and one or more variables with exponents. Like terms (same variable or variables raised to the same power) can be combined to simplify a polynomial. The polynomials can be evaluated by substituting a given value of the variable into each instance of the variable, then using order of operations to complete the calculations.